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{t | s borrower (t[customer -name] = s[customer -name] u loan (u[loan-number ] = s[loan-number ] u[branch-name] = Perryridge ))} In English, this expression is The set of all (customer-name) tuples for which the customer has a loan that is at the Perryridge branch Tuple variable u ensures that the customer is a borrower at the Perryridge branch Tuple variable s is restricted to pertain to the same loan number as s Figure 337 shows the result of this query To nd all customers who have a loan, an account, or both at the bank, we used the union operation in the relational algebra In the tuple relational calculus, we shall need two there exists clauses, connected by or ( ): {t | s borrower (t[customer -name] = s[customer -name]) u depositor (t[customer -name] = u[customer -name])} This expression gives us the set of all customer-name tuples for which at least one of the following holds: The customer-name appears in some tuple of the borrower relation as a borrower from the bank The customer-name appears in some tuple of the depositor relation as a depositor of the bank If some customer has both a loan and an account at the bank, that customer appears only once in the result, because the mathematical de nition of a set does not allow duplicate members The result of this query appeared earlier in Figure 312 If we now want only those customers who have both an account and a loan at the bank, all we need to do is to change the or ( ) to and ( ) in the preceding expression {t | s borrower (t[customer -name] = s[customer -name]) u depositor (t[customer -name] = u[customer -name])} The result of this query appeared in Figure 320 Now consider the query Find all customers who have an account at the bank but do not have a loan from the bank The tuple-relational-calculus expression for this query is similar to the expressions that we have just seen, except for the use of the not ( ) symbol: {t | u depositor (t[customer -name] = u[customer -name]) s borrower (t[customer -name] = s[customer -name])} customer-name Adams Hayes Figure 337 Names of all customers who have a loan at the Perryridge branch.

Standard FTP TCP Port => 1024 TCP Port => 1024 Standard FTP Client TCP Port => 1024 TCP Port => 1024 Passive FTP Client Passive FTP TCP Port = 21 TCP Port => 1024 FTP Server TCP Port = 21 TCP Port = 20 FTP Server

The McGraw Hill Companies, 2001

he last chapter focused on the features of the Cisco ASA security appliances and the various ASA models in the Cisco product lineup Starting with this chapter and continuing through the remainder of this book, I will focus on how to configure your security appliance to meet the requirements outlined in your security policy This chapter will focus on the following two items: Accessing the appliance Becoming familiar with the command-line interface (CLI) of the appliance

3

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Cisco offers three main methods for configuring your security appliance: Command-Line Interface (CLI) Adaptive Security Device Manager (ASDM) Cisco Security Manager (CSM)

This tuple-relational-calculus expression uses the u depositor ( ) clause to require that the customer have an account at the bank, and it uses the s borrower ( ) clause to eliminate those customers who appear in some tuple of the borrower relation as having a loan from the bank The result of this query appeared in Figure 313 The query that we shall consider next uses implication, denoted by The formula P Q means P implies Q ; that is, if P is true, then Q must be true Note that P Q is logically equivalent to P Q The use of implication rather than not and or often suggests a more intuitive interpretation of a query in English Consider the query that we used in Section 323 to illustrate the division operation: Find all customers who have an account at all branches located in Brooklyn To write this query in the tuple relational calculus, we introduce the for all construct, denoted by The notation t r (Q(t)) means Q is true for all tuples t in relation r We write the expression for our query as follows: {t | r customer (r[customer -name] = t[customer -name]) ( u branch (u[branch-city] = Brooklyn s depositor (t[customer -name] = s[customer -name] w account (w[account-number ] = s[account-number ] w[branch-name] = u[branch-name]))))} In English, we interpret this expression as The set of all customers (that is, (customername) tuples t) such that, for all tuples u in the branch relation, if the value of u on attribute branch-city is Brooklyn, then the customer has an account at the branch whose name appears in the branch-name attribute of u Note that there is a subtlety in the above query: If there is no branch in Brooklyn, all customer names satisfy the condition The rst line of the query expression is critical in this case without the condition r customer (r[customer -name] = t[customer -name]) if there is no branch in Brooklyn, any value of t (including values that are not customer names in the depositor relation) would qualify.